9.0 Acid-Base Equilibria Constants & Calculations
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Definitions
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An acid ionises in solution to form H+ ions.
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A base ionises in solution to form OH- ions.
Strength of acid/base
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The strengths of acid and base are dependent on the degree of dissociation.
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Degree of dissociation, α = (Amount Dissociated)/ (Initial Amount)
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Strength of acid depends on
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α, higher the value, the stronger it is
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Independent of [H+] and [OH-]
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Strong acids/bases
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Ionise completely in solution
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α = 1
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[acid] = [H+ aq], *
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[base] = [OH- aq], *
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Weak acids/bases
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Ionise partially in solution
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α < 1
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For weak acid HA,
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HA(aq) ⇌ H+(aq) + A-(aq)
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[HA] >> [H+ aq]
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For weak base B,
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B(aq) + H2O(l) ⇌ HB+(aq) + OH-(aq)
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[B] >> [OH- aq]
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9.1 pH and pOH
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pH
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The pH of a solution is the negative logarithm to the base 10 of the H+ ion concentration in mol dm^-3.
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pH= -log10 [H+]
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pOH
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The pOH of a solution is the negative logarithm to the base 10 of the OH- ion concentration in mol dm^-3.
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pOH= -log10 [OH-]
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pOH + pH = 14
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[H+] = 10^- pH
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[OH-] = 10^- pOH
9.2 Measurement of pH
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Indicators show different colors at a different pH.
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Examples include Universal Indicator, Phenolphthalein, Bromothymol blue and Methyl Orange. (Refer to Mole Concept for pH ranges).
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pH sensor attached to a data logger
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pH meter
9.2.1 Acid Dissociation Constant, Ka, and the use of pKa
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Acid dissociation constant
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HA(aq) ⇌ H+(aq) + A-(aq)
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Ka = ( [H+] [A-] / [HA] ) mol dm^-3, constant at a given temperature.
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Ka is the measure of the strength of the acid.
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Ka increases with temperature since dissociation is endothermic.
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Larger Ka implies stronger acid (higher [H+] and [A-])
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pKa = -log10 Ka
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Smaller pKa implies stronger acid.
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9.2.2 Base Dissociation Constant, Kb, and the use of pKb
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Base dissociation constant
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B(aq) + H2O(l) ⇌ HB+(aq) + OH-(aq)
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Kb = ( [HB+][OH-] / [B] ) mol dm^-3, constant at a given temperature
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Kb is the measure of the strength of a base.
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Kb increases with temperature since dissociation is constant.
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Larger Kb implies stronger base (higher [HB+] and [OH-])
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pKb = -log10 Kb
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Smaller pKb implies stronger base.
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9.3 Ionic Product of Water
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H2O(l) ⇌ H+(aq) + OH-(aq) , ΔH >0
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Kw = [H+ (aq)] [OH- (aq)] mol^2 dm^-6 = Ka x Kb
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Kw = 1.00 * 10 ^-14 mol^2 dm^-6 at 298 K
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[H+ (aq)] = [OH- (aq)] in water
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Constant Kw at constant temperature
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[H+] and [OH-] increase with temperature as dissociation is endothermic.
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[H+ aq] = [OH- aq] so pH does not change.
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pKw = -log10 Kw
9.4 Calculations of [H+ aq]/ [OH- aq] and pH/ pOH
Weak Acid
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Ka = ( [H+][A-] / [HA] ) mol dm^-3 = Cα x Cα / C(1-α)
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α << 1, so (1-a) ≈ 1, Ka = C*α^2
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Alternatively, [H+] = [A-], Ka = [H+]^2 / C
Weak Base
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Kb = C*α^2
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Kb = [OH-]^2 / C
By using the equations, [H+] and [OH-(aq)], and subsequently pH and pOH can be calculated.
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